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10x^2+50x-60=0
a = 10; b = 50; c = -60;
Δ = b2-4ac
Δ = 502-4·10·(-60)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-70}{2*10}=\frac{-120}{20} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+70}{2*10}=\frac{20}{20} =1 $
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